Problem:
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000.
My Solution:
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000.
My Solution:
static void Main(string[] args)
{
int sumOfMultiples = 0;
for (int i = 1; i < 1000; i++)
{
if (i % 3 == 0 || i % 5 == 0)
{
sumOfMultiples += i;
}
}
Console.Write("The Sum of Multiples of 3 or 5 below 1000 is :");
Console.Write(sumOfMultiples);
Console.ReadLine();
}
Note: You can simplifies the coding :)
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