Problem:
2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
What is the sum of the digits of the number 2^1000?
2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
What is the sum of the digits of the number 2^1000?
My Solution:
Note:
You can simplifies the coding :)
- static void Main(string[] args)
- {
- int pwr = 1000;
- int sum = 0;
- BigInteger l =(BigInteger)Math.Pow(2, 1000);
- foreach (var item in l.ToString().ToCharArray())
- {
- sum += Int32.Parse(item.ToString());
- }
- Console.WriteLine(sum);
- Console.ReadLine();
- }
Note:
You can simplifies the coding :)
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